91x^2-108x+32=0

Solution for 91x^2-108x+32=0 equation:

91x^2-108x+32=0

a = 91; b = -108; c = +32;
Δ = b2-4ac
Δ = -1082-4·91·32
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-108)-4}{2*91}=\frac{104}{182}
=4/7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-108)+4}{2*91}=\frac{112}{182}
=8/13
$